3.2295 \(\int (a+b \sqrt [3]{x})^2 x^3 \, dx\)

Optimal. Leaf size=34 \[ \frac {a^2 x^4}{4}+\frac {6}{13} a b x^{13/3}+\frac {3}{14} b^2 x^{14/3} \]

[Out]

1/4*a^2*x^4+6/13*a*b*x^(13/3)+3/14*b^2*x^(14/3)

________________________________________________________________________________________

Rubi [A]  time = 0.03, antiderivative size = 34, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, integrand size = 15, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.133, Rules used = {266, 43} \[ \frac {a^2 x^4}{4}+\frac {6}{13} a b x^{13/3}+\frac {3}{14} b^2 x^{14/3} \]

Antiderivative was successfully verified.

[In]

Int[(a + b*x^(1/3))^2*x^3,x]

[Out]

(a^2*x^4)/4 + (6*a*b*x^(13/3))/13 + (3*b^2*x^(14/3))/14

Rule 43

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d
*x)^n, x], x] /; FreeQ[{a, b, c, d, n}, x] && NeQ[b*c - a*d, 0] && IGtQ[m, 0] && ( !IntegerQ[n] || (EqQ[c, 0]
&& LeQ[7*m + 4*n + 4, 0]) || LtQ[9*m + 5*(n + 1), 0] || GtQ[m + n + 2, 0])

Rule 266

Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Dist[1/n, Subst[Int[x^(Simplify[(m + 1)/n] - 1)*(a
+ b*x)^p, x], x, x^n], x] /; FreeQ[{a, b, m, n, p}, x] && IntegerQ[Simplify[(m + 1)/n]]

Rubi steps

\begin {align*} \int \left (a+b \sqrt [3]{x}\right )^2 x^3 \, dx &=3 \operatorname {Subst}\left (\int x^{11} (a+b x)^2 \, dx,x,\sqrt [3]{x}\right )\\ &=3 \operatorname {Subst}\left (\int \left (a^2 x^{11}+2 a b x^{12}+b^2 x^{13}\right ) \, dx,x,\sqrt [3]{x}\right )\\ &=\frac {a^2 x^4}{4}+\frac {6}{13} a b x^{13/3}+\frac {3}{14} b^2 x^{14/3}\\ \end {align*}

________________________________________________________________________________________

Mathematica [A]  time = 0.03, size = 34, normalized size = 1.00 \[ \frac {a^2 x^4}{4}+\frac {6}{13} a b x^{13/3}+\frac {3}{14} b^2 x^{14/3} \]

Antiderivative was successfully verified.

[In]

Integrate[(a + b*x^(1/3))^2*x^3,x]

[Out]

(a^2*x^4)/4 + (6*a*b*x^(13/3))/13 + (3*b^2*x^(14/3))/14

________________________________________________________________________________________

fricas [A]  time = 0.52, size = 24, normalized size = 0.71 \[ \frac {3}{14} \, b^{2} x^{\frac {14}{3}} + \frac {6}{13} \, a b x^{\frac {13}{3}} + \frac {1}{4} \, a^{2} x^{4} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a+b*x^(1/3))^2*x^3,x, algorithm="fricas")

[Out]

3/14*b^2*x^(14/3) + 6/13*a*b*x^(13/3) + 1/4*a^2*x^4

________________________________________________________________________________________

giac [A]  time = 0.15, size = 24, normalized size = 0.71 \[ \frac {3}{14} \, b^{2} x^{\frac {14}{3}} + \frac {6}{13} \, a b x^{\frac {13}{3}} + \frac {1}{4} \, a^{2} x^{4} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a+b*x^(1/3))^2*x^3,x, algorithm="giac")

[Out]

3/14*b^2*x^(14/3) + 6/13*a*b*x^(13/3) + 1/4*a^2*x^4

________________________________________________________________________________________

maple [A]  time = 0.00, size = 25, normalized size = 0.74 \[ \frac {3 b^{2} x^{\frac {14}{3}}}{14}+\frac {6 a b \,x^{\frac {13}{3}}}{13}+\frac {a^{2} x^{4}}{4} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a+b*x^(1/3))^2*x^3,x)

[Out]

1/4*a^2*x^4+6/13*a*b*x^(13/3)+3/14*b^2*x^(14/3)

________________________________________________________________________________________

maxima [B]  time = 0.92, size = 200, normalized size = 5.88 \[ \frac {3 \, {\left (b x^{\frac {1}{3}} + a\right )}^{14}}{14 \, b^{12}} - \frac {33 \, {\left (b x^{\frac {1}{3}} + a\right )}^{13} a}{13 \, b^{12}} + \frac {55 \, {\left (b x^{\frac {1}{3}} + a\right )}^{12} a^{2}}{4 \, b^{12}} - \frac {45 \, {\left (b x^{\frac {1}{3}} + a\right )}^{11} a^{3}}{b^{12}} + \frac {99 \, {\left (b x^{\frac {1}{3}} + a\right )}^{10} a^{4}}{b^{12}} - \frac {154 \, {\left (b x^{\frac {1}{3}} + a\right )}^{9} a^{5}}{b^{12}} + \frac {693 \, {\left (b x^{\frac {1}{3}} + a\right )}^{8} a^{6}}{4 \, b^{12}} - \frac {990 \, {\left (b x^{\frac {1}{3}} + a\right )}^{7} a^{7}}{7 \, b^{12}} + \frac {165 \, {\left (b x^{\frac {1}{3}} + a\right )}^{6} a^{8}}{2 \, b^{12}} - \frac {33 \, {\left (b x^{\frac {1}{3}} + a\right )}^{5} a^{9}}{b^{12}} + \frac {33 \, {\left (b x^{\frac {1}{3}} + a\right )}^{4} a^{10}}{4 \, b^{12}} - \frac {{\left (b x^{\frac {1}{3}} + a\right )}^{3} a^{11}}{b^{12}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a+b*x^(1/3))^2*x^3,x, algorithm="maxima")

[Out]

3/14*(b*x^(1/3) + a)^14/b^12 - 33/13*(b*x^(1/3) + a)^13*a/b^12 + 55/4*(b*x^(1/3) + a)^12*a^2/b^12 - 45*(b*x^(1
/3) + a)^11*a^3/b^12 + 99*(b*x^(1/3) + a)^10*a^4/b^12 - 154*(b*x^(1/3) + a)^9*a^5/b^12 + 693/4*(b*x^(1/3) + a)
^8*a^6/b^12 - 990/7*(b*x^(1/3) + a)^7*a^7/b^12 + 165/2*(b*x^(1/3) + a)^6*a^8/b^12 - 33*(b*x^(1/3) + a)^5*a^9/b
^12 + 33/4*(b*x^(1/3) + a)^4*a^10/b^12 - (b*x^(1/3) + a)^3*a^11/b^12

________________________________________________________________________________________

mupad [B]  time = 0.04, size = 24, normalized size = 0.71 \[ \frac {a^2\,x^4}{4}+\frac {3\,b^2\,x^{14/3}}{14}+\frac {6\,a\,b\,x^{13/3}}{13} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^3*(a + b*x^(1/3))^2,x)

[Out]

(a^2*x^4)/4 + (3*b^2*x^(14/3))/14 + (6*a*b*x^(13/3))/13

________________________________________________________________________________________

sympy [A]  time = 1.73, size = 31, normalized size = 0.91 \[ \frac {a^{2} x^{4}}{4} + \frac {6 a b x^{\frac {13}{3}}}{13} + \frac {3 b^{2} x^{\frac {14}{3}}}{14} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a+b*x**(1/3))**2*x**3,x)

[Out]

a**2*x**4/4 + 6*a*b*x**(13/3)/13 + 3*b**2*x**(14/3)/14

________________________________________________________________________________________